Oct 17, 2015

Determining Genotypes through Test Crosses and Phenotypic Ratios

In instances where an organism displays a dominant characteristic but its genetic makeup remains uncertain—whether it's homozygous or heterozygous—a test cross is employed. This cross involves pairing the organism with an individual that has a phenotypically recessive trait. In the resulting F1 generation, a 1:1 segregation ratio of dominant to recessive traits signifies that the unknown characteristic is heterozygous in nature.


Test Cross

Illustrative Example: Consider the case of plant height, which can be TT (tall) or Tt (tall):

a) TT x tt = Tt, Tt, Tt, Tt (all tall) indicating a homozygous genotype.

b) Tt x tt = Tt, Tt, tt, tt (2 tall: 2 short, 1:1) suggesting a heterozygous dominant genotype.

Mendel's Concept Supported: Mendel's idea of allele segregation during gamete formation was substantiated through the test cross. This cross entails breeding an organism of unknown genetic composition with one exhibiting a recessive phenotype, ultimately unveiling the genotype of the mysterious organism.

Significance: The test cross validates Mendel's hypothesis of allele segregation. A monohybrid test cross is used to discern whether an individual with a dominant phenotype is homozygous dominant or heterozygous for a specific trait.

Problem Scenario 1: White vs. Black Sheep

Considering sheep coat color, where white is dominant over black, the genotype of a white sheep can be deduced through crossbreeding. A white sheep mated with a black (homozygous) sheep will yield either all white or a 2:2 segregation of white and black offspring.

Solution: White x Black

a) WW x ww = Ww (All white)

b) Ww x ww = WW, Ww, ww, ww (2 white: 2 black)

Problem Scenario 2: Fruit Flies' Wing Length

When a long-winged (L) fruit fly is crossed with a short-winged (I) counterpart, resulting in a 1:1 offspring ratio, the genotypes of all flies involved can be ascertained.

Solution: Long-winged fly x Short-winged fly

Offspring: Ll, Ll, ll, ll (Long-winged: 50%, Short-winged: 50%, 2:2 or 1:1 ratio)